2-(11/n)=-(5/n^2)

Solution for 2-(11/n)=-(5/n^2) equation:

D( n )

n = 0

n^2 = 0

n = 0

n = 0

n^2 = 0

n^2 = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:+oo)

2-(11/n) = -(5/(n^2)) // + 5/(n^2)

5/(n^2)-(11/n)+2 = 0

5/(n^2)-11*n^-1+2 = 0

5*n^-2-11*n^-1+2 = 0

t_1 = n^-1

5*t_1^2-11*t_1^1+2 = 0

5*t_1^2-11*t_1+2 = 0

DELTA = (-11)^2-(2*4*5)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+11)/(2*5) or t_1 = (11-81^(1/2))/(2*5)

t_1 = 2 or t_1 = 1/5

t_1 = 1/5

n^-1-1/5 = 0

1*n^-1 = 1/5 // : 1

n^-1 = 1/5

-1 < 0

1/(n^1) = 1/5 // * n^1

1 = 1/5*n^1 // : 1/5

5 = n^1

n = 5

t_1 = 2

n^-1-2 = 0

1*n^-1 = 2 // : 1

n^-1 = 2

-1 < 0

1/(n^1) = 2 // * n^1

1 = 2*n^1 // : 2

1/2 = n^1

n = 1/2

n in { 5, 1/2 }